1- ¿Como se manifiestan y registran las etapas del crecimiento urbano? 2-¿A qué se llaman AGENTES SOCIALES? Menciónalos. 3-¿Qué es la RED URBANA? 4-¿Cómo se clasifican las JERARQUIAS DE LAS CIUDADES de acuerdo con su centro y su zona de influencia? 5-¿Cómo se diferencian las distintas AREAS o zonas dentro de una ciudad?

1- ¿Como se manifiestan y registran las etapas del crecimiento urbano? 2-¿A qué se llaman AGENTES SOCIALES? Menciónalos. 3-¿Qué es la RED URBANA? 4-¿Cómo se clasifican las JERARQUIAS DE LAS…

Continue Reading 1- ¿Como se manifiestan y registran las etapas del crecimiento urbano? 2-¿A qué se llaman AGENTES SOCIALES? Menciónalos. 3-¿Qué es la RED URBANA? 4-¿Cómo se clasifican las JERARQUIAS DE LAS CIUDADES de acuerdo con su centro y su zona de influencia? 5-¿Cómo se diferencian las distintas AREAS o zonas dentro de una ciudad?

The rotary vacuum filter is the most common piece of equipment used for the extraction of penicillin, and is used after fermentation in order to remove the Penicillium chrysogenum spores from the penicillin-containing medium. Continuous rotary vacuum filtration can be analysed by considering each revolution of the drum as a stationary batch filtration. Per revolution, each cm2 of filter cloth is used to form cake only for the period of time it spends submerged in the liquid reservoir. A rotary drum vacuum filter with drum diameter 2 m and filter width 2 m is used to filter P. chrysogenum spores from the aqueous suspension. The pressure drop is kept constant at 5 psi; the filter operates with 30% of the filter cloth submerged. Laboratory batch tests with a 10 cm2 filter have shown that 500 ml of slurry can be filtered in 23 min at a pressure drop of 12 psi. Previous studies have shown that the filter cake of P. chrysogenum is significantly compressible, and the cake compressibility, s, is 0.5. Assume that the resistance due to the filter medium is negligible. Determine the drum speed required (in revolutions per hour, rph) to produce 20 m3 of filtered liquid per hour.

The rotary vacuum filter is the most common piece of equipment used for the extraction of penicillin, and is used after fermentation in order to remove the Penicillium chrysogenum spores…

Continue Reading The rotary vacuum filter is the most common piece of equipment used for the extraction of penicillin, and is used after fermentation in order to remove the Penicillium chrysogenum spores from the penicillin-containing medium. Continuous rotary vacuum filtration can be analysed by considering each revolution of the drum as a stationary batch filtration. Per revolution, each cm2 of filter cloth is used to form cake only for the period of time it spends submerged in the liquid reservoir. A rotary drum vacuum filter with drum diameter 2 m and filter width 2 m is used to filter P. chrysogenum spores from the aqueous suspension. The pressure drop is kept constant at 5 psi; the filter operates with 30% of the filter cloth submerged. Laboratory batch tests with a 10 cm2 filter have shown that 500 ml of slurry can be filtered in 23 min at a pressure drop of 12 psi. Previous studies have shown that the filter cake of P. chrysogenum is significantly compressible, and the cake compressibility, s, is 0.5. Assume that the resistance due to the filter medium is negligible. Determine the drum speed required (in revolutions per hour, rph) to produce 20 m3 of filtered liquid per hour.

1. ArrayList in Java A bus has a seating capacity of n. The fare depends on the capacity n and the number of passengers on the bus. For example, if there is less than or equal to 25% of passengers currently on the bus, then they will be charged a traveling fare of n+n*0.6. If the passenger count is greater than 25% and less than or equal to 50% of the capacity of the bus, then they will be charged a fare of n+n*0.3. If the number of passengers on the bus is more than 50% of the seating capacity of the bus, then they will be charged a fare of n (If the value on dividing n by 2 or 4 gives a remainder other than 0, then convert it into its ceiling value). You will be given the seating capacity, the number of stops during the trip, an arraylist of strings representing the passenger’s ID prefixed with a “+” or a “-” sign denoting whether the passenger has got on or out of the bus, respectively, and a query q.

1. ArrayList in Java A bus has a seating capacity of n. The fare depends on the capacity n and the number of passengers on the bus. For example, if…

Continue Reading 1. ArrayList in Java A bus has a seating capacity of n. The fare depends on the capacity n and the number of passengers on the bus. For example, if there is less than or equal to 25% of passengers currently on the bus, then they will be charged a traveling fare of n+n*0.6. If the passenger count is greater than 25% and less than or equal to 50% of the capacity of the bus, then they will be charged a fare of n+n*0.3. If the number of passengers on the bus is more than 50% of the seating capacity of the bus, then they will be charged a fare of n (If the value on dividing n by 2 or 4 gives a remainder other than 0, then convert it into its ceiling value). You will be given the seating capacity, the number of stops during the trip, an arraylist of strings representing the passenger’s ID prefixed with a “+” or a “-” sign denoting whether the passenger has got on or out of the bus, respectively, and a query q.

Question B3. A concentric tube heat exchanger is used to cool lubricating oil for a large diesel engine. The inner tube is constructed of 2 mm wall thickness stainless steel, having thermal conductivity 16 W/m K. The flow rate of cooling water through the inner tube (radius = 30 mm) is 0.3 kg/s. The flow rate of oil through the tube (radius = 50 mm) is 0.15 kg/s. Assume fully developed flow, if the oil cooler is to be used to cool oil from 90°C to 50°C using water available at 283K. The overall heat transfer coefficient is 21.9 W/(m²K). Calculate the length of the tube required for parallel (co-current) flow, and the length of the tube required for counter-current flow. The average heat capacity for oil is 2.131 kJ/(kgK) and for the water 4.178 kJ/(kgK).

Question B3. A concentric tube heat exchanger is used to cool lubricating oil for a large diesel engine. The inner tube is constructed of 2 mm wall thickness stainless steel,…

Continue Reading Question B3. A concentric tube heat exchanger is used to cool lubricating oil for a large diesel engine. The inner tube is constructed of 2 mm wall thickness stainless steel, having thermal conductivity 16 W/m K. The flow rate of cooling water through the inner tube (radius = 30 mm) is 0.3 kg/s. The flow rate of oil through the tube (radius = 50 mm) is 0.15 kg/s. Assume fully developed flow, if the oil cooler is to be used to cool oil from 90°C to 50°C using water available at 283K. The overall heat transfer coefficient is 21.9 W/(m²K). Calculate the length of the tube required for parallel (co-current) flow, and the length of the tube required for counter-current flow. The average heat capacity for oil is 2.131 kJ/(kgK) and for the water 4.178 kJ/(kgK).

For the copper-nickel phase diagram in the figure below, find the compositions of the liquid and solid phases for a nominal composition of 60% Ni and 40% Cu at 1316WC (2400 degree F). Use the inverse lever rule to determine the proportions of liquid and solid phases present in the alloy.

For the copper-nickel phase diagram in the figure below, find the compositions of the liquid and solid phases for a nominal composition of 60% Ni and 40% Cu at 1316WC…

Continue Reading For the copper-nickel phase diagram in the figure below, find the compositions of the liquid and solid phases for a nominal composition of 60% Ni and 40% Cu at 1316WC (2400 degree F). Use the inverse lever rule to determine the proportions of liquid and solid phases present in the alloy.

QUESTION 3 (15 MARKS) The following is a summary of the cashbook and the bank statement, which was specially requested for the fest 2 weeks of Devendran Marketing a company specializing in selling frozen foods. AMANAH BANK BERHAD Bank Statement of Devendran Marketing Date Debits Credits RM RM So 250 Particulars Dec 2015 1 Balance Wa 2 0001 4 Standing order 7 Credit transfer 6 Direct debit 7 0002 8 Direct debit 12 Dishonoured cheque 15 Cheque clearance-Radziah Balance RM 800 750 500 2,300 2,220 1.800 80 84 SS 30 2136 2,081 2041 2241 200 CASH BOOK Dec RM RM 2015 1 5 10 Balance Wa Abdul Rashid Aminuddin 800 250 1.500 Dec 2015 1 2 3 4 Wages Azizah Radziah Lola food Supplier Din’s cold Balance / Cheque No 0001 00012 1113 0003 SO 48 200 ISO 0004 5 12 60 2,042 2550 13 Balance la 2.550 2002 Note: i. A cheque (no.0002) paid to Azizah amounting RM48 has been wrongly recorded as RM84 by the bank. A cheque (no.1 113) worth RM200 received from Radziah was wrongly recorded on the credit side of the cash book. L. Required: a. Prepare the Adjusted Cash Book. (6 marks) b. Prepare the Bank Reconciliation Statement as at 15 December 2015. (3 marks) c. Standing order and direct debit are the items recorded in the Bank Statement but yet to be recorded by the business. Differentiate these two (2) items. (4 marks)

QUESTION 3 (15 MARKS) The following is a summary of the cashbook and the bank statement, which was specially requested for the fest 2 weeks of Devendran Marketing a company…

Continue Reading QUESTION 3 (15 MARKS) The following is a summary of the cashbook and the bank statement, which was specially requested for the fest 2 weeks of Devendran Marketing a company specializing in selling frozen foods. AMANAH BANK BERHAD Bank Statement of Devendran Marketing Date Debits Credits RM RM So 250 Particulars Dec 2015 1 Balance Wa 2 0001 4 Standing order 7 Credit transfer 6 Direct debit 7 0002 8 Direct debit 12 Dishonoured cheque 15 Cheque clearance-Radziah Balance RM 800 750 500 2,300 2,220 1.800 80 84 SS 30 2136 2,081 2041 2241 200 CASH BOOK Dec RM RM 2015 1 5 10 Balance Wa Abdul Rashid Aminuddin 800 250 1.500 Dec 2015 1 2 3 4 Wages Azizah Radziah Lola food Supplier Din’s cold Balance / Cheque No 0001 00012 1113 0003 SO 48 200 ISO 0004 5 12 60 2,042 2550 13 Balance la 2.550 2002 Note: i. A cheque (no.0002) paid to Azizah amounting RM48 has been wrongly recorded as RM84 by the bank. A cheque (no.1 113) worth RM200 received from Radziah was wrongly recorded on the credit side of the cash book. L. Required: a. Prepare the Adjusted Cash Book. (6 marks) b. Prepare the Bank Reconciliation Statement as at 15 December 2015. (3 marks) c. Standing order and direct debit are the items recorded in the Bank Statement but yet to be recorded by the business. Differentiate these two (2) items. (4 marks)

Compute the values of the product (1 + 1)(1+)(1+ }). (1+) for small values of n in order to conjecture a general formula for the product. Fill in the blank with your conjecture. (1+1)(1 + 1)(1 + ) … (1+1) – Prove your conjecture by mathematical induction. Proof (by mathematical induction): Let P(n) be the equation ( . We will show that P(n) is true for every integer n 2 1. Show that P(1) is true: Select P(1) from the choices below. O P(1) = 1 + 1 O P(1) = 1 0 (1+1) = 1 +1 0 (1+1)(2 + 1)(1+ 1)(1 + 1) = 1 +2+3 The selected statement is true because both sides of the equation ae equal. Show that for each integer k 2 1, if P(k) is true, then P(k + 1) is true: Let k be any integer with k 2 1, and suppose that P(k) is true. The left-hand side of P(k) is (1 + 1)(1+1)(1+. (C ) and the right-hand side of Pik) is and the right-hand side of P(k) is . [The inductive hypothesis is that the two sides of P(k) are equal.] We must show that Pk + 1) is true. The left-hand side of P(k + 1) is We must show that P(k + 1) is true. The left-hand side of P[k + 1) is (1 + 1)(1 + 1) (1 ++)-( and the right-hand side of P(K + 1) is and the right-hand side of P(K + 1) is . After after substitution from the inductive hypothesis, the left-hand side of P(K + 1) becomes —Selec When the left-hand and right-hand sides of P(k + 1) are simplified, they both can be shown to equal . Hence P(k + 1) is true, which completes the inductive step.

Compute the values of the product (1 + 1)(1+)(1+ }). (1+) for small values of n in order to conjecture a general formula for the product. Fill in the blank…

Continue Reading Compute the values of the product (1 + 1)(1+)(1+ }). (1+) for small values of n in order to conjecture a general formula for the product. Fill in the blank with your conjecture. (1+1)(1 + 1)(1 + ) … (1+1) – Prove your conjecture by mathematical induction. Proof (by mathematical induction): Let P(n) be the equation ( . We will show that P(n) is true for every integer n 2 1. Show that P(1) is true: Select P(1) from the choices below. O P(1) = 1 + 1 O P(1) = 1 0 (1+1) = 1 +1 0 (1+1)(2 + 1)(1+ 1)(1 + 1) = 1 +2+3 The selected statement is true because both sides of the equation ae equal. Show that for each integer k 2 1, if P(k) is true, then P(k + 1) is true: Let k be any integer with k 2 1, and suppose that P(k) is true. The left-hand side of P(k) is (1 + 1)(1+1)(1+. (C ) and the right-hand side of Pik) is and the right-hand side of P(k) is . [The inductive hypothesis is that the two sides of P(k) are equal.] We must show that Pk + 1) is true. The left-hand side of P(k + 1) is We must show that P(k + 1) is true. The left-hand side of P[k + 1) is (1 + 1)(1 + 1) (1 ++)-( and the right-hand side of P(K + 1) is and the right-hand side of P(K + 1) is . After after substitution from the inductive hypothesis, the left-hand side of P(K + 1) becomes —Selec When the left-hand and right-hand sides of P(k + 1) are simplified, they both can be shown to equal . Hence P(k + 1) is true, which completes the inductive step.

Question 1: Assume that the electric field between two charged parallel plates has a magnitude of 200 V/m. Find the change in the electric potential from one point to another in the electric field, for the following three cases: a) 20 cm in the direction of the electric field b) 20 cm in a direction perpendicular to the electric field. c) 3 cm in the direction of the electric field, then 4 cm perpendicular to the field, and then 5 cm back to the original position.

Question 1: Assume that the electric field between two charged parallel plates has a magnitude of 200 V/m. Find the change in the electric potential from one point to another…

Continue Reading Question 1: Assume that the electric field between two charged parallel plates has a magnitude of 200 V/m. Find the change in the electric potential from one point to another in the electric field, for the following three cases: a) 20 cm in the direction of the electric field b) 20 cm in a direction perpendicular to the electric field. c) 3 cm in the direction of the electric field, then 4 cm perpendicular to the field, and then 5 cm back to the original position.

Making appropriate use fo resistor combination techniques, calculate i3, and Vx in the circuit below. 32 (3 l.2 32 52 3 be Using resistace combination and current division as appropriate, determine values of i1, i2, and V3 in the circuit below. In the circuit below, only the voltage Vx is of interest. Simplify the circuit using appropriate resistor combinations and iteratively employ voltage division to determine Vx.

Making appropriate use fo resistor combination techniques, calculate i3, and Vx in the circuit below. 32 (3 l.2 32 52 3 be Using resistace combination and current division as appropriate,…

Continue Reading Making appropriate use fo resistor combination techniques, calculate i3, and Vx in the circuit below. 32 (3 l.2 32 52 3 be Using resistace combination and current division as appropriate, determine values of i1, i2, and V3 in the circuit below. In the circuit below, only the voltage Vx is of interest. Simplify the circuit using appropriate resistor combinations and iteratively employ voltage division to determine Vx.